(x-3)*(x+3)=x*x+12

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Solution for (x-3)*(x+3)=x*x+12 equation: 


Simplifying
(x + -3)(x + 3) = x * x + 12

Reorder the terms:
(-3 + x)(x + 3) = x * x + 12

Reorder the terms:
(-3 + x)(3 + x) = x * x + 12

Multiply (-3 + x) * (3 + x)
(-3(3 + x) + x(3 + x)) = x * x + 12
((3 * -3 + x * -3) + x(3 + x)) = x * x + 12
((-9 + -3x) + x(3 + x)) = x * x + 12
(-9 + -3x + (3 * x + x * x)) = x * x + 12
(-9 + -3x + (3x + x2)) = x * x + 12

Combine like terms: -3x + 3x = 0
(-9 + 0 + x2) = x * x + 12
(-9 + x2) = x * x + 12

Multiply x * x
-9 + x2 = x2 + 12

Reorder the terms:
-9 + x2 = 12 + x2

Add '-1x2' to each side of the equation.
-9 + x2 + -1x2 = 12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-9 + 0 = 12 + x2 + -1x2
-9 = 12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-9 = 12 + 0
-9 = 12

Solving
-9 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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