(x-3)*(x+2)=x-15

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Solution for (x-3)*(x+2)=x-15 equation: 



(x-3)(x+2)=x-15

We move all terms to the left:

(x-3)(x+2)-(x-15)=0

We get rid of parentheses

(x-3)(x+2)-x+15=0

We multiply parentheses ..

(+x^2+2x-3x-6)-x+15=0

We add all the numbers together, and all the variables

(+x^2+2x-3x-6)-1x+15=0

We get rid of parentheses

x^2+2x-3x-1x-6+15=0

We add all the numbers together, and all the variables

x^2-2x+9=0

a = 1; b = -2; c = +9;
Δ = b2-4ac
Δ = -22-4·1·9
Δ = -32
Delta is less than zero, so there is no solution for the equation

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