(x-3)(x-3)+36=x

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Solution for (x-3)(x-3)+36=x equation: 



(x-3)(x-3)+36=x

We move all terms to the left:

(x-3)(x-3)+36-(x)=0

We add all the numbers together, and all the variables

-1x+(x-3)(x-3)+36=0

We multiply parentheses ..

(+x^2-3x-3x+9)-1x+36=0

We get rid of parentheses

x^2-3x-3x-1x+9+36=0

We add all the numbers together, and all the variables

x^2-7x+45=0

a = 1; b = -7; c = +45;
Δ = b2-4ac
Δ = -72-4·1·45
Δ = -131
Delta is less than zero, so there is no solution for the equation

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