(x-3)(x-2)-2=x(x-1)-3x

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Solution for (x-3)(x-2)-2=x(x-1)-3x equation: 



(x-3)(x-2)-2=x(x-1)-3x

We move all terms to the left:

(x-3)(x-2)-2-(x(x-1)-3x)=0

We multiply parentheses ..

(+x^2-2x-3x+6)-(x(x-1)-3x)-2=0



We calculate terms in parentheses: -(x(x-1)-3x), so:

x(x-1)-3x

We add all the numbers together, and all the variables

-3x+x(x-1)

We multiply parentheses

x^2-3x-1x

We add all the numbers together, and all the variables

x^2-4x

Back to the equation:

-(x^2-4x)



We get rid of parentheses

x^2-x^2-2x-3x+4x+6-2=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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