(x-3)(x+4)=x2+4

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Solution for (x-3)(x+4)=x2+4 equation: 



(x-3)(x+4)=x2+4

We move all terms to the left:

(x-3)(x+4)-(x2+4)=0

We add all the numbers together, and all the variables

-(+x^2+4)+(x-3)(x+4)=0

We get rid of parentheses

-x^2+(x-3)(x+4)-4=0

We multiply parentheses ..

-x^2+(+x^2+4x-3x-12)-4=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+4x-3x-12)-4=0

We get rid of parentheses

-1x^2+x^2+4x-3x-12-4=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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