(x-3)(x+4)=3x

Solution for (x-3)(x+4)=3x equation:

(x-3)(x+4)=3x

We move all terms to the left:

(x-3)(x+4)-(3x)=0

We add all the numbers together, and all the variables

-3x+(x-3)(x+4)=0

We multiply parentheses ..

(+x^2+4x-3x-12)-3x=0

We get rid of parentheses

x^2+4x-3x-3x-12=0

We add all the numbers together, and all the variables

x^2-2x-12=0

a = 1; b = -2; c = -12;
Δ = b2-4ac
Δ = -22-4·1·(-12)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{13}}{2*1}=\frac{2-2\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{13}}{2*1}=\frac{2+2\sqrt{13}}{2}
$