(x-3)(x+4)=(x*x)+4

Solution for (x-3)(x+4)=(x*x)+4 equation:

(x-3)(x+4)=(x*x)+4

We move all terms to the left:

(x-3)(x+4)-((x*x)+4)=0

We add all the numbers together, and all the variables

(x-3)(x+4)-((+x*x)+4)=0

We multiply parentheses ..

(+x^2+4x-3x-12)-((+x*x)+4)=0


We calculate terms in parentheses: -((+x*x)+4), so:

(+x*x)+4

We get rid of parentheses

x*x+4

Wy multiply elements

x^2+4

Back to the equation:

-(x^2+4)


We get rid of parentheses

x^2-x^2+4x-3x-12-4=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16