(x-3)(x+4)-2(3x-2)=(x-4)(x-4)

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Solution for (x-3)(x+4)-2(3x-2)=(x-4)(x-4) equation: 



(x-3)(x+4)-2(3x-2)=(x-4)(x-4)

We move all terms to the left:

(x-3)(x+4)-2(3x-2)-((x-4)(x-4))=0

We multiply parentheses

(x-3)(x+4)-6x-((x-4)(x-4))+4=0

We multiply parentheses ..

(+x^2+4x-3x-12)-6x-((x-4)(x-4))+4=0



We calculate terms in parentheses: -((x-4)(x-4)), so:

(x-4)(x-4)

We multiply parentheses ..

(+x^2-4x-4x+16)

We get rid of parentheses

x^2-4x-4x+16

We add all the numbers together, and all the variables

x^2-8x+16

Back to the equation:

-(x^2-8x+16)



We get rid of parentheses

x^2-x^2+4x-3x-6x+8x-12-16+4=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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