(x-3)(x+3)+5=0

Solution for (x-3)(x+3)+5=0 equation:

Simplifying
(x + -3)(x + 3) + 5 = 0

Reorder the terms:
(-3 + x)(x + 3) + 5 = 0

Reorder the terms:
(-3 + x)(3 + x) + 5 = 0

Multiply (-3 + x) * (3 + x)
(-3(3 + x) + x(3 + x)) + 5 = 0
((3 * -3 + x * -3) + x(3 + x)) + 5 = 0
((-9 + -3x) + x(3 + x)) + 5 = 0
(-9 + -3x + (3 * x + x * x)) + 5 = 0
(-9 + -3x + (3x + x2)) + 5 = 0

Combine like terms: -3x + 3x = 0
(-9 + 0 + x2) + 5 = 0
(-9 + x2) + 5 = 0

Reorder the terms:
-9 + 5 + x2 = 0

Combine like terms: -9 + 5 = -4
-4 + x2 = 0

Solving
-4 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + x2 = 0 + 4
x2 = 0 + 4

Combine like terms: 0 + 4 = 4
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}