(x-20)+(2x-111)+((1/2)x+10)=180

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Solution for (x-20)+(2x-111)+((1/2)x+10)=180 equation:



(x-20)+(2x-111)+((1/2)x+10)=180
We move all terms to the left:
(x-20)+(2x-111)+((1/2)x+10)-(180)=0
Domain of the equation: 2)x+10)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(x-20)+(2x-111)+((+1/2)x+10)-180=0
We get rid of parentheses
x+2x+((+1/2)x+10)-20-111-180=0
We multiply all the terms by the denominator
x*2)x+10)+2x*2)x+10)+((+1-20*2)x+10)-111*2)x+10)-180*2)x+10)=0
We add all the numbers together, and all the variables
x*2)x+10)+2x*2)x+10)+((-39)x+10)-111*2)x+10)-180*2)x+10)=0
Wy multiply elements
16x^5=0
We do not support expression: x^5

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