(x-2)=(3x+4)/3

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Solution for (x-2)=(3x+4)/3 equation: 



(x-2)=(3x+4)/3

We move all terms to the left:

(x-2)-((3x+4)/3)=0

We get rid of parentheses

x-((3x+4)/3)-2=0

We multiply all the terms by the denominator


x*3)-((3x+4)-2*3)=0

We add all the numbers together, and all the variables

x*3)-((3x+4)=0

Wy multiply elements

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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