(x-2)/7=2+(3-x)/14

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Solution for (x-2)/7=2+(3-x)/14 equation: 



(x-2)/7=2+(3-x)/14

We move all terms to the left:

(x-2)/7-(2+(3-x)/14)=0

We add all the numbers together, and all the variables

(x-2)/7-(2+(-1x+3)/14)=0

We calculate fractions


x/()+(-(2+(-1x+3)*7)/()=0



We calculate terms in parentheses: +(-(2+(-1x+3)*7)/(), so:

-(2+(-1x+3)*7)/(

We multiply all the terms by the denominator


-(2+(-1x+3)*7)



We calculate terms in parentheses: -(2+(-1x+3)*7), so:

2+(-1x+3)*7

determiningTheFunctionDomain
(-1x+3)*7+2

We multiply parentheses

-7x+21+2

We add all the numbers together, and all the variables

-7x+23

Back to the equation:

-(-7x+23)



We get rid of parentheses

7x-23

Back to the equation:

+(7x-23)



We get rid of parentheses

x/()+7x-23=0

We multiply all the terms by the denominator


x+7x*()-23*()=0

We add all the numbers together, and all the variables

x+7x*()=0

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