(x-2)/7=(2x+1)/4

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Solution for (x-2)/7=(2x+1)/4 equation: 



(x-2)/7=(2x+1)/4

We move all terms to the left:

(x-2)/7-((2x+1)/4)=0

We calculate fractions


x/()+(-((2x+1)*7)/()=0



We calculate terms in parentheses: +(-((2x+1)*7)/(), so:

-((2x+1)*7)/(

We multiply all the terms by the denominator


-((2x+1)*7)



We calculate terms in parentheses: -((2x+1)*7), so:

(2x+1)*7

We multiply parentheses

14x+7

Back to the equation:

-(14x+7)



We get rid of parentheses

-14x-7

Back to the equation:

+(-14x-7)



We get rid of parentheses

x/()-14x-7=0

We multiply all the terms by the denominator


x-14x*()-7*()=0

We add all the numbers together, and all the variables

x-14x*()=0

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