(x-2)/(x+2)+6(x-2)/x-6)=1

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Solution for (x-2)/(x+2)+6(x-2)/x-6)=1 equation:



(x-2)/(x+2)+6(x-2)/x-6)=1
We move all terms to the left:
(x-2)/(x+2)+6(x-2)/x-6)-(1)=0
Domain of the equation: (x+2)!=0
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
Domain of the equation: x!=0
x∈R
We add all the numbers together, and all the variables
(x-2)/(x+2)+6(x-2)/x=0
We calculate fractions
(x^2-2x)/(x^2+2x)+(6(x-2)*(x+2))/(x^2+2x)=0
We calculate terms in parentheses: +(6(x-2)*(x+2))/(x^2+2x), so:
6(x-2)*(x+2))/(x^2+2x
We add all the numbers together, and all the variables
2x+6(x-2)*(x+2))/(x^2
We multiply all the terms by the denominator
2x*(x^2+6(x-2)*(x+2))
Back to the equation:
+(2x*(x^2+6(x-2)*(x+2)))
We multiply all the terms by the denominator
(x^2-2x)+((2x*(x^2+6(x-2)*(x+2))))*(x^2+2x)=0
We calculate terms in parentheses: +((2x*(x^2+6(x-2)*(x+2))))*(x^2+2x), so:
(2x*(x^2+6(x-2)*(x+2))))*(x^2+2x
We add all the numbers together, and all the variables
2x+(2x*(x^2+6(x-2)*(x+2))))*(x^2
Back to the equation:
+(2x+(2x*(x^2+6(x-2)*(x+2))))*(x^2)
We get rid of parentheses
x^2-2x+(2x+(2x*(x^2+6(x-2)*(x+2))))*x^2=0

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