(x-2)-(3x+2)=5(x+4)+1

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Solution for (x-2)-(3x+2)=5(x+4)+1 equation: 



(x-2)-(3x+2)=5(x+4)+1

We move all terms to the left:

(x-2)-(3x+2)-(5(x+4)+1)=0

We get rid of parentheses

x-3x-(5(x+4)+1)-2-2=0



We calculate terms in parentheses: -(5(x+4)+1), so:

5(x+4)+1

We multiply parentheses

5x+20+1

We add all the numbers together, and all the variables

5x+21

Back to the equation:

-(5x+21)



We add all the numbers together, and all the variables

-2x-(5x+21)-4=0

We get rid of parentheses

-2x-5x-21-4=0

We add all the numbers together, and all the variables

-7x-25=0

We move all terms containing x to the left, all other terms to the right

-7x=25

x=25/-7

x=-3+4/7

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