(x-2)+x=6(x+3)-4x

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Solution for (x-2)+x=6(x+3)-4x equation: 



(x-2)+x=6(x+3)-4x

We move all terms to the left:

(x-2)+x-(6(x+3)-4x)=0

We add all the numbers together, and all the variables

x+(x-2)-(6(x+3)-4x)=0

We get rid of parentheses

x+x-(6(x+3)-4x)-2=0



We calculate terms in parentheses: -(6(x+3)-4x), so:

6(x+3)-4x

We add all the numbers together, and all the variables

-4x+6(x+3)

We multiply parentheses

-4x+6x+18

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

2x-(2x+18)-2=0

We get rid of parentheses

2x-2x-18-2=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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