(x-2)(x-2)=(x+2)(x+2)

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Solution for (x-2)(x-2)=(x+2)(x+2) equation: 



(x-2)(x-2)=(x+2)(x+2)

We move all terms to the left:

(x-2)(x-2)-((x+2)(x+2))=0

We multiply parentheses ..

(+x^2-2x-2x+4)-((x+2)(x+2))=0



We calculate terms in parentheses: -((x+2)(x+2)), so:

(x+2)(x+2)

We multiply parentheses ..

(+x^2+2x+2x+4)

We get rid of parentheses

x^2+2x+2x+4

We add all the numbers together, and all the variables

x^2+4x+4

Back to the equation:

-(x^2+4x+4)



We get rid of parentheses

x^2-x^2-2x-2x-4x+4-4=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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