(x-2)(x+3)=x2-4

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Solution for (x-2)(x+3)=x2-4 equation: 



(x-2)(x+3)=x2-4

We move all terms to the left:

(x-2)(x+3)-(x2-4)=0

We add all the numbers together, and all the variables

-(+x^2-4)+(x-2)(x+3)=0

We get rid of parentheses

-x^2+(x-2)(x+3)+4=0

We multiply parentheses ..

-x^2+(+x^2+3x-2x-6)+4=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+3x-2x-6)+4=0

We get rid of parentheses

-1x^2+x^2+3x-2x-6+4=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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