(x-2)(x+2)-12=0

Solution for (x-2)(x+2)-12=0 equation:

Simplifying
(x + -2)(x + 2) + -12 = 0

Reorder the terms:
(-2 + x)(x + 2) + -12 = 0

Reorder the terms:
(-2 + x)(2 + x) + -12 = 0

Multiply (-2 + x) * (2 + x)
(-2(2 + x) + x(2 + x)) + -12 = 0
((2 * -2 + x * -2) + x(2 + x)) + -12 = 0
((-4 + -2x) + x(2 + x)) + -12 = 0
(-4 + -2x + (2 * x + x * x)) + -12 = 0
(-4 + -2x + (2x + x2)) + -12 = 0

Combine like terms: -2x + 2x = 0
(-4 + 0 + x2) + -12 = 0
(-4 + x2) + -12 = 0

Reorder the terms:
-4 + -12 + x2 = 0

Combine like terms: -4 + -12 = -16
-16 + x2 = 0

Solving
-16 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + x2 = 0 + 16
x2 = 0 + 16

Combine like terms: 0 + 16 = 16
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}