(x-2)(9x+5)=(3x+2)(3x-5)

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Solution for (x-2)(9x+5)=(3x+2)(3x-5) equation: 



(x-2)(9x+5)=(3x+2)(3x-5)

We move all terms to the left:

(x-2)(9x+5)-((3x+2)(3x-5))=0

We multiply parentheses ..

(+9x^2+5x-18x-10)-((3x+2)(3x-5))=0



We calculate terms in parentheses: -((3x+2)(3x-5)), so:

(3x+2)(3x-5)

We multiply parentheses ..

(+9x^2-15x+6x-10)

We get rid of parentheses

9x^2-15x+6x-10

We add all the numbers together, and all the variables

9x^2-9x-10

Back to the equation:

-(9x^2-9x-10)



We get rid of parentheses

9x^2-9x^2+5x-18x+9x-10+10=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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