(x-2)(5-x)=4-x2

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Solution for (x-2)(5-x)=4-x2 equation: 



(x-2)(5-x)=4-x2

We move all terms to the left:

(x-2)(5-x)-(4-x2)=0

We add all the numbers together, and all the variables

-(-1x^2+4)+(x-2)(-1x+5)=0

We get rid of parentheses

1x^2+(x-2)(-1x+5)-4=0

We multiply parentheses ..

1x^2+(-1x^2+5x+2x-10)-4=0

We add all the numbers together, and all the variables

x^2+(-1x^2+5x+2x-10)-4=0

We get rid of parentheses

x^2-1x^2+5x+2x-10-4=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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