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(x-2)(2x+7)=2x^2-3x
We move all terms to the left:
(x-2)(2x+7)-(2x^2-3x)=0
We get rid of parentheses
-2x^2+(x-2)(2x+7)+3x=0
We multiply parentheses ..
-2x^2+(+2x^2+7x-4x-14)+3x=0
We get rid of parentheses
-2x^2+2x^2+7x-4x+3x-14=0
We add all the numbers together, and all the variables
6x-14=0
We move all terms containing x to the left, all other terms to the right
6x=14
x=14/6
x=2+1/3
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