(x-19)(x+19)=0

Solution for (x-19)(x+19)=0 equation:

(x-19)(x+19)=0

We use the square of the difference formula

x^2-361=0

a = 1; b = 0; c = -361;
Δ = b2-4ac
Δ = 02-4·1·(-361)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-38}{2*1}=\frac{-38}{2}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+38}{2*1}=\frac{38}{2}
=19
$