(x-18)+x+(2x-4)+92=382

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Solution for (x-18)+x+(2x-4)+92=382 equation: 



(x-18)+x+(2x-4)+92=382

We move all terms to the left:

(x-18)+x+(2x-4)+92-(382)=0

We add all the numbers together, and all the variables

x+(x-18)+(2x-4)-290=0

We get rid of parentheses

x+x+2x-18-4-290=0

We add all the numbers together, and all the variables

4x-312=0

We move all terms containing x to the left, all other terms to the right

4x=312

x=312/4

x=78

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