(x-12)=(x2+2x-7)

Solution for (x-12)=(x2+2x-7) equation:

(x-12)=(x2+2x-7)

We move all terms to the left:

(x-12)-((x2+2x-7))=0

We add all the numbers together, and all the variables

-((+x^2+2x-7))+(x-12)=0

We get rid of parentheses

-((+x^2+2x-7))+x-12=0


We calculate terms in parentheses: -((+x^2+2x-7)), so:

(+x^2+2x-7)

We get rid of parentheses

x^2+2x-7

Back to the equation:

-(x^2+2x-7)


We add all the numbers together, and all the variables

x-(x^2+2x-7)-12=0

We get rid of parentheses

-x^2+x-2x+7-12=0

We add all the numbers together, and all the variables

-1x^2-1x-5=0

a = -1; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation