(x-12)+62=3x+10

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Solution for (x-12)+62=3x+10 equation: 



(x-12)+62=3x+10

We move all terms to the left:

(x-12)+62-(3x+10)=0

We get rid of parentheses

x-3x-12-10+62=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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