(x-11)(2x-31)=0

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Solution for (x-11)(2x-31)=0 equation:



(x-11)(2x-31)=0
We multiply parentheses ..
(+2x^2-31x-22x+341)=0
We get rid of parentheses
2x^2-31x-22x+341=0
We add all the numbers together, and all the variables
2x^2-53x+341=0
a = 2; b = -53; c = +341;
Δ = b2-4ac
Δ = -532-4·2·341
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-9}{2*2}=\frac{44}{4} =11 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+9}{2*2}=\frac{62}{4} =15+1/2 $

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