(x-10)(x+14)=(x+14)(x-20)

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Solution for (x-10)(x+14)=(x+14)(x-20) equation: 



(x-10)(x+14)=(x+14)(x-20)

We move all terms to the left:

(x-10)(x+14)-((x+14)(x-20))=0

We multiply parentheses ..

(+x^2+14x-10x-140)-((x+14)(x-20))=0



We calculate terms in parentheses: -((x+14)(x-20)), so:

(x+14)(x-20)

We multiply parentheses ..

(+x^2-20x+14x-280)

We get rid of parentheses

x^2-20x+14x-280

We add all the numbers together, and all the variables

x^2-6x-280

Back to the equation:

-(x^2-6x-280)



We get rid of parentheses

x^2-x^2+14x-10x+6x-140+280=0

We add all the numbers together, and all the variables

10x+140=0

We move all terms containing x to the left, all other terms to the right

10x=-140

x=-140/10

x=-14

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