(x-1)/2=(3x+4)/3

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Solution for (x-1)/2=(3x+4)/3 equation: 



(x-1)/2=(3x+4)/3

We move all terms to the left:

(x-1)/2-((3x+4)/3)=0

We calculate fractions


x/()+(-((3x+4)*2)/()=0



We calculate terms in parentheses: +(-((3x+4)*2)/(), so:

-((3x+4)*2)/(

We multiply all the terms by the denominator


-((3x+4)*2)



We calculate terms in parentheses: -((3x+4)*2), so:

(3x+4)*2

We multiply parentheses

6x+8

Back to the equation:

-(6x+8)



We get rid of parentheses

-6x-8

Back to the equation:

+(-6x-8)



We get rid of parentheses

x/()-6x-8=0

We multiply all the terms by the denominator


x-6x*()-8*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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