(x-1)/(x+1)=2/3x

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Solution for (x-1)/(x+1)=2/3x equation:


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(x-1)/(x+1) = (2/3)*x // - (2/3)*x

(x-1)/(x+1)-((2/3)*x) = 0

(x-1)/(x+1)+(-2/3)*x = 0

(x-1)/(x+1)+(-2*x)/3 = 0

(3*(x-1))/(3*(x+1))+(-2*x*(x+1))/(3*(x+1)) = 0

3*(x-1)-2*x*(x+1) = 0

x-2*x^2-3 = 0

x-2*x^2-3 = 0

x-2*x^2-3 = 0

DELTA = 1^2-(-3*(-2)*4)

DELTA = -23

DELTA < 0

1 = 0

1/(3*(x+1)) = 0

1/(3*(x+1)) = 0 // * 3*(x+1)

1 = 0

x belongs to the empty set

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