(x-1)+6x=4(3x-1)+2

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Solution for (x-1)+6x=4(3x-1)+2 equation: 



(x-1)+6x=4(3x-1)+2

We move all terms to the left:

(x-1)+6x-(4(3x-1)+2)=0

We add all the numbers together, and all the variables

6x+(x-1)-(4(3x-1)+2)=0

We get rid of parentheses

6x+x-(4(3x-1)+2)-1=0



We calculate terms in parentheses: -(4(3x-1)+2), so:

4(3x-1)+2

We multiply parentheses

12x-4+2

We add all the numbers together, and all the variables

12x-2

Back to the equation:

-(12x-2)



We add all the numbers together, and all the variables

7x-(12x-2)-1=0

We get rid of parentheses

7x-12x+2-1=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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