(x-1)+(2x+3)+(3x-2)=180

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Solution for (x-1)+(2x+3)+(3x-2)=180 equation: 



(x-1)+(2x+3)+(3x-2)=180

We move all terms to the left:

(x-1)+(2x+3)+(3x-2)-(180)=0

We get rid of parentheses

x+2x+3x-1+3-2-180=0

We add all the numbers together, and all the variables

6x-180=0

We move all terms containing x to the left, all other terms to the right

6x=180

x=180/6

x=30

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