(x-1)(x-7)=2(x-3)(x-4)

Solution for (x-1)(x-7)=2(x-3)(x-4) equation:

(x-1)(x-7)=2(x-3)(x-4)

We move all terms to the left:

(x-1)(x-7)-(2(x-3)(x-4))=0

We multiply parentheses ..

(+x^2-7x-1x+7)-(2(x-3)(x-4))=0


We calculate terms in parentheses: -(2(x-3)(x-4)), so:

2(x-3)(x-4)

We multiply parentheses ..

2(+x^2-4x-3x+12)

We multiply parentheses

2x^2-8x-6x+24

We add all the numbers together, and all the variables

2x^2-14x+24

Back to the equation:

-(2x^2-14x+24)


We get rid of parentheses

x^2-2x^2-7x-1x+14x+7-24=0

We add all the numbers together, and all the variables

-1x^2+6x-17=0

a = -1; b = 6; c = -17;
Δ = b2-4ac
Δ = 62-4·(-1)·(-17)
Δ = -32
Delta is less than zero, so there is no solution for the equation