(x-1)(x-7)=(x1)(x-3)

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Solution for (x-1)(x-7)=(x1)(x-3) equation: 



(x-1)(x-7)=(x1)(x-3)

We move all terms to the left:

(x-1)(x-7)-((x1)(x-3))=0

We multiply parentheses ..

(+x^2-7x-1x+7)-(x1(x-3))=0



We calculate terms in parentheses: -(x1(x-3)), so:

x1(x-3)

We multiply parentheses

x^2-3x

Back to the equation:

-(x^2-3x)



We get rid of parentheses

x^2-x^2-7x-1x+3x+7=0

We add all the numbers together, and all the variables

-5x+7=0

We move all terms containing x to the left, all other terms to the right

-5x=-7

x=-7/-5

x=1+2/5

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