(x-1)(x-7)=(x-1)(x+3)

Solution for (x-1)(x-7)=(x-1)(x+3) equation:

(x-1)(x-7)=(x-1)(x+3)

We move all terms to the left:

(x-1)(x-7)-((x-1)(x+3))=0

We multiply parentheses ..

(+x^2-7x-1x+7)-((x-1)(x+3))=0


We calculate terms in parentheses: -((x-1)(x+3)), so:

(x-1)(x+3)

We multiply parentheses ..

(+x^2+3x-1x-3)

We get rid of parentheses

x^2+3x-1x-3

We add all the numbers together, and all the variables

x^2+2x-3

Back to the equation:

-(x^2+2x-3)


We get rid of parentheses

x^2-x^2-7x-1x-2x+7+3=0

We add all the numbers together, and all the variables

-10x+10=0

We move all terms containing x to the left, all other terms to the right

-10x=-10

x=-10/-10

x=1