(x-1)(x-2)=(x-3)

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Solution for (x-1)(x-2)=(x-3) equation:



(x-1)(x-2)=(x-3)
We move all terms to the left:
(x-1)(x-2)-((x-3))=0
We multiply parentheses ..
(+x^2-2x-1x+2)-((x-3))=0
We calculate terms in parentheses: -((x-3)), so:
(x-3)
We get rid of parentheses
x-3
Back to the equation:
-(x-3)
We get rid of parentheses
x^2-2x-1x-x+2+3=0
We add all the numbers together, and all the variables
x^2-4x+5=0
a = 1; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·1·5
Δ = -4
Delta is less than zero, so there is no solution for the equation

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