(x-1)(x-2)(x-3)(x-4)-1=0

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Solution for (x-1)(x-2)(x-3)(x-4)-1=0 equation: 



(x-1)(x-2)(x-3)(x-4)-1=0

We multiply parentheses ..

(+x^2-2x-1x+2)(x-3)(x-4)-1=0

We multiply parentheses ..

(+x^2-2x-1x+2)(+x^2-4x-3x+12)-1=0

We move all terms containing x to the left, all other terms to the right

(+x^2-2x-1x+2)(+x^2-4x-3x+12)=1

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