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(x-1)(x-10)=x
We move all terms to the left:
(x-1)(x-10)-(x)=0
We add all the numbers together, and all the variables
-1x+(x-1)(x-10)=0
We multiply parentheses ..
(+x^2-10x-1x+10)-1x=0
We get rid of parentheses
x^2-10x-1x-1x+10=0
We add all the numbers together, and all the variables
x^2-12x+10=0
a = 1; b = -12; c = +10;
Δ = b2-4ac
Δ = -122-4·1·10
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{26}}{2*1}=\frac{12-2\sqrt{26}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{26}}{2*1}=\frac{12+2\sqrt{26}}{2} $
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