(x-1)(x-1)=(x+5)(x+3)

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Solution for (x-1)(x-1)=(x+5)(x+3) equation: 



(x-1)(x-1)=(x+5)(x+3)

We move all terms to the left:

(x-1)(x-1)-((x+5)(x+3))=0

We multiply parentheses ..

(+x^2-1x-1x+1)-((x+5)(x+3))=0



We calculate terms in parentheses: -((x+5)(x+3)), so:

(x+5)(x+3)

We multiply parentheses ..

(+x^2+3x+5x+15)

We get rid of parentheses

x^2+3x+5x+15

We add all the numbers together, and all the variables

x^2+8x+15

Back to the equation:

-(x^2+8x+15)



We get rid of parentheses

x^2-x^2-1x-1x-8x+1-15=0

We add all the numbers together, and all the variables

-10x-14=0

We move all terms containing x to the left, all other terms to the right

-10x=14

x=14/-10

x=-1+2/5

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