(x-1)(x+8)=14

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Solution for (x-1)(x+8)=14 equation:



(x-1)(x+8)=14
We move all terms to the left:
(x-1)(x+8)-(14)=0
We multiply parentheses ..
(+x^2+8x-1x-8)-14=0
We get rid of parentheses
x^2+8x-1x-8-14=0
We add all the numbers together, and all the variables
x^2+7x-22=0
a = 1; b = 7; c = -22;
Δ = b2-4ac
Δ = 72-4·1·(-22)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{137}}{2*1}=\frac{-7-\sqrt{137}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{137}}{2*1}=\frac{-7+\sqrt{137}}{2} $

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