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(x-1)(x+5)=x=4x-2
We move all terms to the left:
(x-1)(x+5)-(x)=0
We add all the numbers together, and all the variables
-1x+(x-1)(x+5)=0
We multiply parentheses ..
(+x^2+5x-1x-5)-1x=0
We get rid of parentheses
x^2+5x-1x-1x-5=0
We add all the numbers together, and all the variables
x^2+3x-5=0
a = 1; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·1·(-5)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{29}}{2*1}=\frac{-3-\sqrt{29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{29}}{2*1}=\frac{-3+\sqrt{29}}{2} $
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