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(x-1)(x+2)=(x-2)(x+2)
We move all terms to the left:
(x-1)(x+2)-((x-2)(x+2))=0
We use the square of the difference formula
x^2+(x-1)(x+2)+4=0
We multiply parentheses ..
x^2+(+x^2+2x-1x-2)+4=0
We get rid of parentheses
x^2+x^2+2x-1x-2+4=0
We add all the numbers together, and all the variables
2x^2+x+2=0
a = 2; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·2·2
Δ = -15
Delta is less than zero, so there is no solution for the equation
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