(x-1)(x+2)=(x+5)(x-3)

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Solution for (x-1)(x+2)=(x+5)(x-3) equation: 



(x-1)(x+2)=(x+5)(x-3)

We move all terms to the left:

(x-1)(x+2)-((x+5)(x-3))=0

We multiply parentheses ..

(+x^2+2x-1x-2)-((x+5)(x-3))=0



We calculate terms in parentheses: -((x+5)(x-3)), so:

(x+5)(x-3)

We multiply parentheses ..

(+x^2-3x+5x-15)

We get rid of parentheses

x^2-3x+5x-15

We add all the numbers together, and all the variables

x^2+2x-15

Back to the equation:

-(x^2+2x-15)



We get rid of parentheses

x^2-x^2+2x-1x-2x-2+15=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13

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