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(x-1)(x+11)=360
We move all terms to the left:
(x-1)(x+11)-(360)=0
We multiply parentheses ..
(+x^2+11x-1x-11)-360=0
We get rid of parentheses
x^2+11x-1x-11-360=0
We add all the numbers together, and all the variables
x^2+10x-371=0
a = 1; b = 10; c = -371;
Δ = b2-4ac
Δ = 102-4·1·(-371)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-12\sqrt{11}}{2*1}=\frac{-10-12\sqrt{11}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+12\sqrt{11}}{2*1}=\frac{-10+12\sqrt{11}}{2} $
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