(x-1)(x+1)=(x+3)(x-2)+2x-7

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Solution for (x-1)(x+1)=(x+3)(x-2)+2x-7 equation: 



(x-1)(x+1)=(x+3)(x-2)+2x-7

We move all terms to the left:

(x-1)(x+1)-((x+3)(x-2)+2x-7)=0

We use the square of the difference formula

x^2-((x+3)(x-2)+2x-7)-1=0

We multiply parentheses ..

x^2-((+x^2-2x+3x-6)+2x-7)-1=0



We calculate terms in parentheses: -((+x^2-2x+3x-6)+2x-7), so:

(+x^2-2x+3x-6)+2x-7

We get rid of parentheses

x^2-2x+3x+2x-6-7

We add all the numbers together, and all the variables

x^2+3x-13

Back to the equation:

-(x^2+3x-13)



We get rid of parentheses

x^2-x^2-3x+13-1=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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