(x-1)(x+1)(x-2)=0

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Solution for (x-1)(x+1)(x-2)=0 equation:


Simplifying
(x + -1)(x + 1)(x + -2) = 0

Reorder the terms:
(-1 + x)(x + 1)(x + -2) = 0

Reorder the terms:
(-1 + x)(1 + x)(x + -2) = 0

Reorder the terms:
(-1 + x)(1 + x)(-2 + x) = 0

Multiply (-1 + x) * (1 + x)
(-1(1 + x) + x(1 + x))(-2 + x) = 0
((1 * -1 + x * -1) + x(1 + x))(-2 + x) = 0
((-1 + -1x) + x(1 + x))(-2 + x) = 0
(-1 + -1x + (1 * x + x * x))(-2 + x) = 0
(-1 + -1x + (1x + x2))(-2 + x) = 0

Combine like terms: -1x + 1x = 0
(-1 + 0 + x2)(-2 + x) = 0
(-1 + x2)(-2 + x) = 0

Multiply (-1 + x2) * (-2 + x)
(-1(-2 + x) + x2(-2 + x)) = 0
((-2 * -1 + x * -1) + x2(-2 + x)) = 0
((2 + -1x) + x2(-2 + x)) = 0
(2 + -1x + (-2 * x2 + x * x2)) = 0
(2 + -1x + (-2x2 + x3)) = 0
(2 + -1x + -2x2 + x3) = 0

Solving
2 + -1x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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