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(x-1)(2x+5)=90
We move all terms to the left:
(x-1)(2x+5)-(90)=0
We multiply parentheses ..
(+2x^2+5x-2x-5)-90=0
We get rid of parentheses
2x^2+5x-2x-5-90=0
We add all the numbers together, and all the variables
2x^2+3x-95=0
a = 2; b = 3; c = -95;
Δ = b2-4ac
Δ = 32-4·2·(-95)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{769}}{2*2}=\frac{-3-\sqrt{769}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{769}}{2*2}=\frac{-3+\sqrt{769}}{4} $
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