(x+yi)(1+2i)=8+6i

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Solution for (x+yi)(1+2i)=8+6i equation: 


Simplifying
(x + yi)(1 + 2i) = 8 + 6i

Reorder the terms:
(iy + x)(1 + 2i) = 8 + 6i

Multiply (iy + x) * (1 + 2i)
(iy(1 + 2i) + x(1 + 2i)) = 8 + 6i
((1 * iy + 2i * iy) + x(1 + 2i)) = 8 + 6i
((1iy + 2i2y) + x(1 + 2i)) = 8 + 6i
(1iy + 2i2y + (1 * x + 2i * x)) = 8 + 6i

Reorder the terms:
(1iy + 2i2y + (2ix + 1x)) = 8 + 6i
(1iy + 2i2y + (2ix + 1x)) = 8 + 6i

Reorder the terms:
(2ix + 1iy + 2i2y + 1x) = 8 + 6i
(2ix + 1iy + 2i2y + 1x) = 8 + 6i

Solving
2ix + 1iy + 2i2y + 1x = 8 + 6i

Solving for variable 'i'.

Reorder the terms:
-8 + -6i + 2ix + 1iy + 2i2y + 1x = 8 + 6i + -8 + -6i

Reorder the terms:
-8 + -6i + 2ix + 1iy + 2i2y + 1x = 8 + -8 + 6i + -6i

Combine like terms: 8 + -8 = 0
-8 + -6i + 2ix + 1iy + 2i2y + 1x = 0 + 6i + -6i
-8 + -6i + 2ix + 1iy + 2i2y + 1x = 6i + -6i

Combine like terms: 6i + -6i = 0
-8 + -6i + 2ix + 1iy + 2i2y + 1x = 0

The solution to this equation could not be determined.

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