(x+y+2)(x-y)-5=0

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Solution for (x+y+2)(x-y)-5=0 equation: 


Simplifying
(x + y + 2)(x + -1y) + -5 = 0

Reorder the terms:
(2 + x + y)(x + -1y) + -5 = 0

Multiply (2 + x + y) * (x + -1y)
(2(x + -1y) + x(x + -1y) + y(x + -1y)) + -5 = 0
((x * 2 + -1y * 2) + x(x + -1y) + y(x + -1y)) + -5 = 0
((2x + -2y) + x(x + -1y) + y(x + -1y)) + -5 = 0
(2x + -2y + (x * x + -1y * x) + y(x + -1y)) + -5 = 0

Reorder the terms:
(2x + -2y + (-1xy + x2) + y(x + -1y)) + -5 = 0
(2x + -2y + (-1xy + x2) + y(x + -1y)) + -5 = 0
(2x + -2y + -1xy + x2 + (x * y + -1y * y)) + -5 = 0
(2x + -2y + -1xy + x2 + (xy + -1y2)) + -5 = 0

Reorder the terms:
(2x + -1xy + xy + x2 + -2y + -1y2) + -5 = 0

Combine like terms: -1xy + xy = 0
(2x + 0 + x2 + -2y + -1y2) + -5 = 0
(2x + x2 + -2y + -1y2) + -5 = 0

Reorder the terms:
-5 + 2x + x2 + -2y + -1y2 = 0

Solving
-5 + 2x + x2 + -2y + -1y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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