(x+x)-(x2)=0.99

Solution for (x+x)-(x2)=0.99 equation:

(x+x)-(x2)=0.99

We move all terms to the left:

(x+x)-(x2)-(0.99)=0

We add all the numbers together, and all the variables

(+2x)-x2-(0.99)=0

We add all the numbers together, and all the variables

-1x^2+(+2x)-0.99=0

We get rid of parentheses

-1x^2+2x-0.99=0

a = -1; b = 2; c = -0.99;
Δ = b2-4ac
Δ = 22-4·(-1)·(-0.99)
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{0.04}}{2*-1}=\frac{-2-\sqrt{0.04}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{0.04}}{2*-1}=\frac{-2+\sqrt{0.04}}{-2}
$